Maninagar, Ahmedabad, India - 380028.
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English Proficient
Hindi Proficient
UNIVERSITY RAJASTHAN 2008
Bachelor of Engineering (B.E.)
Niit 2005
C language
Jlj financial and management consultant 2007
Java
London city college 2008
Post graduate diploma in business management
Near, Gopal Tower, Maninagar Railway Station Rd, Maninagar
Maninagar, Ahmedabad, India - 380028
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2 Students Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
6
Board
CBSE, State
State boards taught
Gujarat State Board
CBSE Subjects taught
Mathematics, Science
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
6
Board
CBSE, State
State boards taught
Gujarat State Board
CBSE Subjects taught
Mathematics, Science
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
6
Board
CBSE, State
State boards taught
Gujarat State Board
CBSE Subjects taught
Mathematics, Science
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
6
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
Yes
4.8 out of 5 28 reviews
Patel Riya
Class 9 Tuition
"You are amazing at what you do! Your passion and dedication is beyond words! Thank you for getting me through this hard quick semester.Thank you so much once again! "
Reply by Sonal
Thanks for feedback
Harsh
Class 9 Tuition
"Mam teaches us very well,she explain us each topic in detail and also clear the base of every topic. I like her method of teaching. "
Reply by Sonal
Thanks for feedback
Rahi Patel
Class 7 Tuition
"I like the teaching way. it was so smart. I am enjoying studying with sonal mam and her teaching way is brilliant. "
Reply by Sonal
Thanks for feedback
Atharv
Class 7 Tuition
"The best explanation is given. Even though I am a weak student now I feel that I am improving and getting better day by day."
Reply by Sonal
Thanks for feedback
1. Which school boards of Class 10 do you teach for?
CBSE and State
2. Do you have any prior teaching experience?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 6 years.
Answered on 12/03/2020 Learn Tuition
Answered on 12/03/2020 Learn IT Courses/Business Objects Enterprise XI
Answered on 02/08/2019 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Coordinate geometry/NCERT Solutions/Exercise 7.1
(i) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(4 – 2)2 + (1 - 3)2}
=> D = √{22 + (-2)2}
=> D = √{4 + 4}
=> D = √8
=> D = 2√2
(ii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-1 + 5)2 + (3 - 7)2}
=> D = √{42 + (-4)2}
=> D = √{16 + 16}
=> D = √32
=> D = 4√2
(iii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-a - a)2 + (-b - b)2}
=> D = √{(-2a)2 + (-2b)2}
=> D = √{4a2 + 4b2}
=> D = 2√(a2 + b2)
Answered on 02/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Polynomials/NCERT Solutions/Exercise 2.1
2 Students Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
6
Board
CBSE, State
State boards taught
Gujarat State Board
CBSE Subjects taught
Mathematics, Science
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
6
Board
CBSE, State
State boards taught
Gujarat State Board
CBSE Subjects taught
Mathematics, Science
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
6
Board
CBSE, State
State boards taught
Gujarat State Board
CBSE Subjects taught
Mathematics, Science
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
6
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
Yes
Answered on 12/03/2020 Learn Tuition
Answered on 12/03/2020 Learn IT Courses/Business Objects Enterprise XI
Answered on 02/08/2019 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Coordinate geometry/NCERT Solutions/Exercise 7.1
(i) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(4 – 2)2 + (1 - 3)2}
=> D = √{22 + (-2)2}
=> D = √{4 + 4}
=> D = √8
=> D = 2√2
(ii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-1 + 5)2 + (3 - 7)2}
=> D = √{42 + (-4)2}
=> D = √{16 + 16}
=> D = √32
=> D = 4√2
(iii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-a - a)2 + (-b - b)2}
=> D = √{(-2a)2 + (-2b)2}
=> D = √{4a2 + 4b2}
=> D = 2√(a2 + b2)
Answered on 02/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Polynomials/NCERT Solutions/Exercise 2.1
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