UrbanPro
true
Suman Ghosh Engineering Entrance trainer in Bangalore

Suman Ghosh

SME in Mathematics & Statistics

J P Nagar, Bangalore, India - 560078.

8 Students

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Suman Ghosh

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I am an IIT Kanpur alumni (MSc Mathematics, NET, GATE) with more than 8 years of working experience in academics and industry.

Languages Spoken

Hindi

Bengali

English

Education

IIT Kanpur 2006

Master of Science (M.Sc.)

Address

J P Nagar, Bangalore, India - 560078

Verified Info

Phone Verified

Email Verified

Report this Profile

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

IIT JAM Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

MSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in MSc Tuition

9

Subject

Mathematics, Statistics

Taught in School or College

No

Teaching Experience in detail in MSc Tuition

I am teaching since 2006 on week ends mainly for the competitive exams in the areas of Mathematical Sciences (pure and applied mathematics, statistics, Operations Research). I personally like to teach on building the foundation for mathematical thinking such that it will help in the long run to clear the competitive exams.

BBA Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

UGC NET Exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

I am willing to Travel

Tutor's Home

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CSIR NET classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Courses

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach BBA Tuition, BSc Tuition, CSIR NET, Engineering Entrance Coaching, IIT JAM Coaching, MSc Tuition and UGC NET Exam Coaching Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Suman Ghosh (92)

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

|z-2|<8 ? (x -- 2)2 + y2 < 64 The area (x -- 2)2 + y2 < 64 is interior of the circle (x -- 2)2 + y2 = 64. The circle (x -- 2)2 + y2 = 64 has centre (2, 0) and radius 8. |z-1|<|z-5| ? (x -- 1)2 < (x -- 5)2 ? 1 -- 2x < 25 -- 10x ? 8x < 24 ? x < 3 The area x < 3 is marked to the left of the straight... ...more
|z-2|<8 ? (x – 2)2 + y2 < 64 The area (x – 2)2 + y2 < 64 is interior of the circle (x – 2)2 + y2 = 64. The circle (x – 2)2 + y2 = 64 has centre (2, 0) and radius 8. |z-1|<|z-5| ? (x – 1)2 < (x – 5)2 ? 1 – 2x < 25 – 10x ? 8x < 24 ? x < 3 The area x < 3 is marked to the left of the straight line x = 3. The line x = 3 is parallel to y axis intersecting x axis at (3, 0). The resultant area will be the common intersection zone of the above two areas.
Answers 7 Comments
Dislike Bookmark

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

To find roots of the equation x3 - 1 = 0 x3 - 1 = 0 (x - 1)(x2 + x + 1) = 0 Since x3 - 1 = 0 is a polynomial equation of degree 3, it will have three roots. We can see that one of the roots is 1. The other 2 roots are complex roots. Let one of them is w. Then it will satisfy the equation. (w -... ...more
To find roots of the equation x3 - 1 = 0 x3 - 1 = 0 (x - 1)(x2 + x + 1) = 0 Since x3 - 1 = 0 is a polynomial equation of degree 3, it will have three roots. We can see that one of the roots is 1. The other 2 roots are complex roots. Let one of them is w. Then it will satisfy the equation. (w - 1)(w2 + w + 1) = 0 w cannot be 1. Hence, w2 + w + 1 = 0 If w is a root, we can see that w2 is another root. Since, w2 + w + 1 = 0, we can say that sum of cube roots of unity is zero.
Answers 7 Comments
Dislike Bookmark

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

n is odd, then n - 1, n + 1, 2n, 3n + 1 are even. n is odd, then 4n is even. Hence, 4n + 1 is odd. So correct option is (E)
Answers 18 Comments
Dislike Bookmark

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

a and b are integers greater than 100 such that a + b = 300 If we take a = 180 and b = 120, the ratio of a to b is 3 to 2. Hence, correct option is (E)
Answers 9 Comments
Dislike Bookmark

Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

IIT JAM Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

MSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in MSc Tuition

9

Subject

Mathematics, Statistics

Taught in School or College

No

Teaching Experience in detail in MSc Tuition

I am teaching since 2006 on week ends mainly for the competitive exams in the areas of Mathematical Sciences (pure and applied mathematics, statistics, Operations Research). I personally like to teach on building the foundation for mathematical thinking such that it will help in the long run to clear the competitive exams.

BBA Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

UGC NET Exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

I am willing to Travel

Tutor's Home

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CSIR NET classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Courses

No Reviews yet!

Answers by Suman Ghosh (92)

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

|z-2|<8 ? (x -- 2)2 + y2 < 64 The area (x -- 2)2 + y2 < 64 is interior of the circle (x -- 2)2 + y2 = 64. The circle (x -- 2)2 + y2 = 64 has centre (2, 0) and radius 8. |z-1|<|z-5| ? (x -- 1)2 < (x -- 5)2 ? 1 -- 2x < 25 -- 10x ? 8x < 24 ? x < 3 The area x < 3 is marked to the left of the straight... ...more
|z-2|<8 ? (x – 2)2 + y2 < 64 The area (x – 2)2 + y2 < 64 is interior of the circle (x – 2)2 + y2 = 64. The circle (x – 2)2 + y2 = 64 has centre (2, 0) and radius 8. |z-1|<|z-5| ? (x – 1)2 < (x – 5)2 ? 1 – 2x < 25 – 10x ? 8x < 24 ? x < 3 The area x < 3 is marked to the left of the straight line x = 3. The line x = 3 is parallel to y axis intersecting x axis at (3, 0). The resultant area will be the common intersection zone of the above two areas.
Answers 7 Comments
Dislike Bookmark

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

To find roots of the equation x3 - 1 = 0 x3 - 1 = 0 (x - 1)(x2 + x + 1) = 0 Since x3 - 1 = 0 is a polynomial equation of degree 3, it will have three roots. We can see that one of the roots is 1. The other 2 roots are complex roots. Let one of them is w. Then it will satisfy the equation. (w -... ...more
To find roots of the equation x3 - 1 = 0 x3 - 1 = 0 (x - 1)(x2 + x + 1) = 0 Since x3 - 1 = 0 is a polynomial equation of degree 3, it will have three roots. We can see that one of the roots is 1. The other 2 roots are complex roots. Let one of them is w. Then it will satisfy the equation. (w - 1)(w2 + w + 1) = 0 w cannot be 1. Hence, w2 + w + 1 = 0 If w is a root, we can see that w2 is another root. Since, w2 + w + 1 = 0, we can say that sum of cube roots of unity is zero.
Answers 7 Comments
Dislike Bookmark

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

n is odd, then n - 1, n + 1, 2n, 3n + 1 are even. n is odd, then 4n is even. Hence, 4n + 1 is odd. So correct option is (E)
Answers 18 Comments
Dislike Bookmark

Answered on 17/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

a and b are integers greater than 100 such that a + b = 300 If we take a = 180 and b = 120, the ratio of a to b is 3 to 2. Hence, correct option is (E)
Answers 9 Comments
Dislike Bookmark

Contact

Load More

Suman Ghosh describes himself as SME in Mathematics & Statistics. He conducts classes in BBA Tuition, BSc Tuition and CSIR NET. Suman is located in J P Nagar, Bangalore. Suman takes Regular Classes- at his Home and Online Classes- via online medium. He has 9 years of teaching experience . Suman has completed Master of Science (M.Sc.) from IIT Kanpur in 2006. He is well versed in Hindi, Bengali and English.

X

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

Different batches available for this Course

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more