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Write a programme to swap two numbers with out using a third variable and by using bitwise op-erators.

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/* Swap a and b */ a ^= b ^= a ^= b ;
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Computer Science Tutor

a=a+b // a*b // a^b b=a-b // a/b // b^a a=a-b // a/b // a^b
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Tuition Classes

main(){ int a=5,b=10; printf("\r\n Before Swap"); printf("\r\na=%d and b=%d",a,b); a^=b^=a^=b; printf("\r\n After Swap"); printf("\r\na=%d and b=%d",a,b); return 0; }
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Tutor

a=a^b; b=a^b a=a^b
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Technical Corporate Trainer

User XOR ( ^ ) x = x ^ y; y = x ^ y; x = x ^ y;
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SUDHIR SHARMA - Computer Trainer based On Delhi

Hi, Ranjeeth.... It's very simple.. just open the following link... http://includehelp.com/c-programs/c-bitwise-programs-to-swap-two-numbers-using-bitwise-operator.aspx
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Tutor

a = a-b b = a+b a = b-a
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XOR of 10 (In Binary 1010) and 5 (In Binary 0101) is 1111 and XOR of 7 (0111) and 5 (0101) is (0010).So the code is --------------------------------------- int x = 10, y = 5; x = x ^ y; // x now becomes 15 (1111) y = x ^ y; // y becomes 10 (1010) x = x ^ y; // x becomes 5 (0101)
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Embedded software engineer

It won't exchange the numbers because you given power symbol so it multiplies and display the multiplied value upto the range of data type what you used(int), and First of all it shows an error in between num1 and Num1. C language is case sensitive. If u want to exchange the numbers here is the formula...
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It won't exchange the numbers because you given power symbol so it multiplies and display the multiplied value upto the range of data type what you used(int), and First of all it shows an error in between num1 and Num1. C language is case sensitive. If u want to exchange the numbers here is the formula follow. temp = num1; num1 = num2; num2 = temp; execute using this formula it will exchange and will show read less
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int a = 5; int b=6; a=a+b; b= a-b; a=a-b;
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