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A box of oranges is inspected by examining three randomly selected oranges drawn without replacement. If all the three oranges are good, the box is approved for sale, otherwise, it is rejected. Find the probability that a box containing 15 oranges out of which 12 are good and 3 are bad ones will be approved for sale.

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Total teaching experiences is 26 year's of 11 and 12

Box contains 12 good and 3 bad oranges if 3 oranges selected are good once the box is approved for sale. Probability of selected 3 good oranges =12×11×10/15×14×13=44/91.
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Let A, B, and C be the respective events that the first, second, and third drawn orange is good. Therefore, probability that first drawn orange is good, P (A) The oranges are not replaced. Therefore, probability of getting second orange good, P (B) = Similarly, probability of getting third orange good,...
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Let A, B, and C be the respective events that the first, second, and third drawn orange is good.

Therefore, probability that first drawn orange is good, P (A)

The oranges are not replaced.

Therefore, probability of getting second orange good, P (B) =

Similarly, probability of getting third orange good, P(C)

The box is approved for sale, if all the three oranges are good.

Thus, probability of getting all the oranges good

Therefore, the probability that the box is approved for sale is

read less
Comments

Related Questions

The probability of obtaining an even prime number on each die, when a pair of dice is rolled is

(A) 0 (B)  (C)  (D) 

When two dice are rolled, the number of outcomes is 36. The only even prime number is 2. Let E be the event of getting an even prime number on each die. ∴ E = {(2, 2)} Therefore, the correct answer is D.
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