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Derive an equation for the path of a projectile fired parallel to horizontal.

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Let the initial velocity be u m/s. angle of projection = 0 initial component of velocity in vertical direction = 0 horizontal displacement from initial position at t= 0sec, = x = u t vertical displacement from initial position at t = 0 0sec, = y = -1/2 g t² so t = x/u Hence ...
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Let the initial velocity be u m/s. angle of projection = 0 initial component of velocity in vertical direction = 0 horizontal displacement from initial position at t= 0sec, = x = u t vertical displacement from initial position at t = 0 0sec, = y = -1/2 g t² so t = x/u Hence y = - 1/2 g (x/u)² = - (g/2u²) x² read less
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