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What is the oxidation state of Ni in Ni (CO)4?

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Reveal Chemystery with 2 years teaching experience in engineering college

The oxidation state of Ni is zero due to zero charge on CO.
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MSc chemistry

Ni oxidation state is 0 in Ni(CO)4 because CO is neutral
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Zero
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Tutor, The ultimate solution to the fear of Organic Chemistry, PhD from DRDO in Chemical Science.

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula x + nL + Nvse = 18...
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Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula

x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)

For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.

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Zero. It is the exceptional case in which the two paired electron of s orbital are get unpaired.
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Tutor, The ultimate solution to the fear of Organic Chemistry, PhD from DRDO in Chemical Science.

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula x + nL + Nvse = 18...
read more

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula

x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)

For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.

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zero
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Chemistry wizard

Zero
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Trainer

Zero, because CO is neutral ligands.
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Chemistry Tutor

The oxidation state of nickel is zero. Since CO(carbonyl) has is neutral and have no charge.
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