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17 + 6p = 9 Transposing 17 to R.H.S, we obtain 6p = 9 − 17 6p = −8 Dividing both sides by 6, we obtain
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17 + 6p = 9

Transposing 17 to R.H.S, we obtain

6p = 9 − 17

6p = −8

Dividing both sides by 6, we obtain

 

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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

6p+17=9 6p=9-17=-8 p=-8/6=-4/3
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