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What are the criterias for similarity of triangles?

Asked by Jasleen 12/11/2016 Last Modified 30/01/2018

6 Answers

Learn Mathematics +2 Class IX-X Tuition Similarity

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Related Questions

What is the fee for 10th grade math and science

Rs 250/- hour

Nishant

5 0

What I should do study for coming in merit list of 10th board exam?

Spend more time on revising the topics which you have learn and concentrate on areas where you are weak. If you follow this you can definitely fetch a good score. If devote your full dedication and time...

Hole

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107

Find the zeroes of the quadratic polynomial x2 + 5x + 6 and verify the relationship between the zeroes and the coefficients.

Let P(x)=x2+5x+6=0 x2+3x+2x+6=0 (x+3)(x+2)=0 x=-3,-2 If ax2+bx+c=0 is a general form of polynomial with degree 2 Sum of zeroes is -b/a Product of zeroes is c/a From the above polynomial Sum of zeroes -3-2=-5=-5/1=-b/a Product...

Rekha

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What is the fees for peivate tuition for 10th State board and CBSE board for Mathematics?

Depending upon the area in which you are going to give classes but according to me it should be at least â?¹6000-7000 per month

Shyam Cholera

0 0

It is necessary to join tutions in 9th class?

clearing concept is necessary. if u do not, in future u going to have lot of difficulty. that much I cant explain here. for example trigonometry is basic here in 9th, I have seen engineering students...

Akash

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The Completing the Square Method

In this video, we'll study "The Completing the Square Method"

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Maths- ur best friend.

Its understanding of urs about the maths that matters a lot. There are some learning tips which helps you a lot. 1. Be relaxed and dont take too much tension. 2. Try to learn concept first and then...

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X Algebra (Maharashtra board 2020)

Solve √(x/y)= 4 (1/x)+(1/y)= 1/(xy) Solution √(x/y)=4 Squaring both sides x/y=16 x=16y x-16y=0 <-eqn1 (1/x)+(1/y)=1/(xy) ((y+x)/xy)=(1/xy) x+y=1 <-eqn2 Multiply by 16 16x+16y=16...

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Exponential Form = 100 = 102, where 2 is the power of 10. Laws of exponents: a-m = 1/ am a m * an = am*n am * an = am*n (am)n = am*n am / bm = (a/b)m a0= 1 (a / b)-m = (b/a)m (-1)odd = -1 (-1)even = 1 ( am / an ) = am-n

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