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The sum of three consecutive even integers is 108. What are the integers?

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35+36+37 = 108
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35+36+37
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x=first integer x+1=second integer x+1+1=third integer (x)+(x+1)+(x+1+1)=108 3x+3=108 Let's isolate x... Let's subtract 3 from both sides... -3+3x+3=108-3 3x=105 Let's divide both sides by 3... (3x)/3=105/3 x=35 Hence the integers are 35, 36, 37 Let's check our work... 35+36+37...
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34,36,38
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35,36,37
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35,36,37
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34, 36, 38
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34 36 38
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Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108. Thus, 3x+6=108. So, x=34, x+2 = 36, x+4= 38 =108.
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34 36 38
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