Sector 11, Dwarka, Delhi, India - 110075.
1
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English Mother Tongue (Native)
Shyama prasad mukherjee college for women Pursuing
Bachelor of Education (B.Ed.)
Sector 11, Dwarka, Delhi, India - 110075
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Fees
₹ 300 per hour
Board
CBSE
CBSE Subjects taught
Mathematics, EVS, Computers, Science, Hindi, Sanskrit, English
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
3
Board
CBSE
CBSE Subjects taught
Sanskrit, Mathematics, Computers, Science, Social Science, Hindi, EVS
Taught in School or College
No
Teaching Experience in detail in Class 8 Tuition
I m from du and I have experience of 1 year
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
CBSE
CBSE Subjects taught
Mathematics, Sanskrit, English, Computers, Science, Social Science, Hindi, EVS
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
CBSE
CBSE Subjects taught
Mathematics, English, Computers, Science, Social Science, Hindi, EVS
Taught in School or College
No
1. Which school boards of Class 1-5 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class I-V Tuition and Class VI-VIII Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 23/05/2020 Learn Tuition
5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx
Rearranging the terms: => 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0
Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero.
So all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0.
∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴ x:y:z= 1:1:1.
Answered on 23/05/2020 Learn Tuition
Answered on 19/05/2020 Learn Tuition
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Fees
₹ 300 per hour
Board
CBSE
CBSE Subjects taught
Mathematics, EVS, Computers, Science, Hindi, Sanskrit, English
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
3
Board
CBSE
CBSE Subjects taught
Sanskrit, Mathematics, Computers, Science, Social Science, Hindi, EVS
Taught in School or College
No
Teaching Experience in detail in Class 8 Tuition
I m from du and I have experience of 1 year
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
CBSE
CBSE Subjects taught
Mathematics, Sanskrit, English, Computers, Science, Social Science, Hindi, EVS
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
CBSE
CBSE Subjects taught
Mathematics, English, Computers, Science, Social Science, Hindi, EVS
Taught in School or College
No
Answered on 23/05/2020 Learn Tuition
5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx
Rearranging the terms: => 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0
Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero.
So all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0.
∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴ x:y:z= 1:1:1.
Answered on 23/05/2020 Learn Tuition
Answered on 19/05/2020 Learn Tuition
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Sector 11, Dwarka, Delhi 
