Bara Putki, Dhanbad, India - 828116.
1
Details verified of Sonali K.✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
Hindi Basic
Dav public school Pursuing
12
Bara Putki, Dhanbad, India - 828116
Phone Verified
Email Verified
Report this Profile
Is this listing inaccurate or duplicate? Any other problem?
Please tell us about the problem and we will fix it.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Handwriting classes
1
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Board
CBSE
CBSE Subjects taught
English, Hindi
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
1. Which classes do you teach?
I teach Class I-V Tuition, Handwriting and Hindi Language Classes.
2. Do you provide a demo class?
No, I don't provide a demo class.
3. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 22/05/2020 Learn Tuition
5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx
Rearranging the terms: =>
2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0
Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero.
So, all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0. ∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴
x:y:z =1:1:1
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Hobby/Handwriting
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Handwriting classes
1
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Board
CBSE
CBSE Subjects taught
English, Hindi
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Answered on 22/05/2020 Learn Tuition
5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx
Rearranging the terms: =>
2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0
Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero.
So, all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0. ∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴
x:y:z =1:1:1
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Hobby/Handwriting
Want to learn from Sonali K.?
Share this Profile
Recommended Profiles
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.
Maholi, Maholi 
