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Find Best Class 12 Tuition in Arya Nagar, Ghaziabad

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Class 12 Tuition in Arya Nagar, Ghaziabad

Select from 54 Online & Offline Class 12 Tuition in your locality

1
Arya Nagar, Ghaziabad
14 yrs of Exp
600per hour
Classes: Class 12 Tuition, BA Tuition and more.

I am quite confident that whatever I am doing and I am capable to handle weak students enough. I have given 100 %result in cbse board examination...

2
Arya Nagar, Ghaziabad
9 yrs of Exp
Classes: Class 12 Tuition, Class 10 Tuition and more.

I am teaching students from 2012 regularly full Time. And I have industrial experience also. So come and gain better knowledge in account and make...

3
Arya Nagar, Ghaziabad
2 yrs of Exp1 student
Classes: Class 12 Tuition, Class 6 Tuition and more.

I can teach each and every topics very easily and make it stronger for the students.

Do you need help in finding the best teacher matching your requirements?

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4
Arya Nagar, Ghaziabad
5 yrs of Exp
600per hour
Classes: Class 12 Tuition, Class 11 Tuition and more.

I had completed my M.Tech (biotechnology) from NIT ALLAHABAD.From last six year i am teaching biology to class 9th and 10th and zoology for NEET.

5
Arya Nagar, Ghaziabad
4 yrs of Exp
Classes: Class 12 Tuition, Class 9 Tuition and more.

BY degree i am an engineer , after graduation i am preparing for civil services , i took coaching from India's most prestige institute for my general...

6
Arya Nagar, Ghaziabad
1 yrs of Exp
800per hour
Classes: Class 12 Tuition, Class 11 Tuition

I have recently completed my post graduation from national institute of technology Karnataka in chemical science.I have also cleared IIT JAM national...

7
Arya Nagar, Ghaziabad
2 yrs of Exp
400per hour
Classes: Class 12 Tuition, Class 10 Tuition

I am a engineer by profession and i am giving home tuition since 2017.I have a degree in bachelor of technology and i have effective communication...

8
Arya Nagar, Ghaziabad
Classes: Class 12 Tuition, Class 11 Tuition and more.

I am an engineer and currently I am working as a Research Assistant at Indian Institute of Science, Bangalore. I am proficient in maths, science,...

9
Arya Nagar, Ghaziabad
Classes: Class 12 Tuition, Class 10 Tuition and more.

Abc computer institute provides Tally Software classes, C Language Classes, C++ Language classes, Web Development Classes, Web Designing Classes,...

10
Arya Nagar, Ghaziabad
1 yrs of Exp
Classes: Class 12 Tuition, Class 11 Tuition and more.

I can teach a commerce student also. I can give students better and easy thoughts. I can Teach students to solve out their problems in both Hindi...

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    Key highlights about Class 12 Tuition

    ✅ Free Demo Class : Available
    ✅ Average price : ₹450/hr
    ✅ Tutors available : 54
    ✅ Class format : Online or Offline classes

    FAQ

    How do I find the best Class 12 Tuition in Arya Nagar, Ghaziabad near me?

    You can browse the list of best Class 12 Tuition tutors on UrbanPro.com. You can even book a free demo class to decide which Tutor to start classes with. Visit UrbanPro to find the best Tutor for Class 12 Tuition

    What is the typical Fee charged for Class 12 Tuition in Arya Nagar, Ghaziabad?

    The fee charged varies between online and offline classes. Generally you get the best quality at the lowest cost in the online classes, as the best tutors don’t like to travel to the Student’s location. Check Fees for various classes on UrbanPro

    Monthly Fee for 1-1 Classes

    ₹4,800 - ₹6,000 for 12 classes per month

    Hourly Fee for 1-1 Classes

    ₹400 - ₹500

    Monthly Fee for Group Classes

    ₹3,840 - ₹4,800 for 12 classes per month

    Hourly Fee for Group Classes

    ₹320 - ₹400

    Monthly Fee for Class 12 Tuition at home

    ₹4,800 - ₹7,200 for 12 classes per month

    Hourly Fee for Class 12 Tuition at home

    ₹400 - ₹600

    Monthly Fee for Online Class 12 Tuition

    ₹4,800 - ₹6,000 for 12 classes per month

    Hourly Fee for Online Class 12 Tuition

    ₹400 - ₹500

    Does joining Class 12 Tuition help?

    It definitely helps to join Class 12 Tuition in Arya Nagar, Ghaziabad, as you get the desired motivation from a Teacher to learn. If you need personal attention and if your budget allows, select 1-1 Class. If you need peer interaction or have budget constraints, select a Group Class. To explore options: Class 12 Tuition in Arya Nagar, Ghaziabad

    Where can I find Class 12 Tuition near me?

    UrbanPro has a list of best Class 12 Tuition To see the entire list see: Class 12 Tuition in Arya Nagar, Ghaziabad.

    Looking for Class 12 Tuition ?

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    Class 12 Tuition Questions

    Find out the name of the microbes from which Cyclosporin A (an immunosuppressive drug) and Statins (blood cholesterol lowering agents) are obtained.

    Drug Function Microbe 1. Cyclosporine −A Immunosuppressive drug Trichoderma polysporum 2. Statin...

    How much is chemical engineering related to chemistry?

    Chemical engineers have a general knowledge of chemistry, but their main focus is detailed knowledge...

    How do I study total chemistry for JEE mains?

    Studying Total Chemistry for JEE Mains Preparing for JEE Mains requires a strategic approach, especially...

    Class 12 Tuition Lessons

    Failing in relatively easy subjects - remedies

    Often most parents complains that their ward cleared many hard subjects but could not cleared the easy subject. The students perception about the subject...

    Vectors

    What is Vector? Scalar quantities are quantities that have only magnitudes such as time, area and distance. Vector quantities are quantities...

    Rule Of Sign

    1. Rule of sign solving is known as VBODMAS: V stands for "Vinculum" or "Bar" B stands for "Bracket" (order as small,medium,big) O stands for "Of" D...

    What are Reserves & Provisions? Lets understand in detail-

    Provisions:There are some expenses and losses which are specific to incur, but their amount cannot be known with certainty as they are not yet incurred....

    Solution to a integration problem

    ∫ sin‾¹ ( x ) dx Let's solve this using integration by parts Let u = sin‾¹ x ∴ du = 1/√( 1 - x² ) dx ...

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