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Answered on 19 Apr Learn Probability
Sadika
To find the probability that two different friends have different birthdays, we can consider the total number of possible combinations of birthdays and the number of combinations where the birthdays are different.
In a non-leap year, there are 365 days. Therefore, the probability that two friends have different birthdays is the complement of the probability that they have the same birthday.
Total number of possible combinations of birthdays: Each friend can have their birthday on any of the 365 days of the year. So, the total number of possible combinations of birthdays for two friends is 365×365365×365.
Number of combinations where the birthdays are different: If one friend has their birthday on a specific day, the other friend can have their birthday on any of the other 364 days of the year. So, the number of combinations where the birthdays are different is 365×364365×364.
Now, let's calculate the probability that two different friends have different birthdays:
Probability=Number of combinations where the birthdays are differentTotal number of possible combinations of birthdays
read lessAnswered on 19 Apr Learn Probability
Sadika
To find the probability of not drawing a white marble, we need to consider the total number of marbles in the box and the number of marbles that are not white.
Given:
Answered on 19 Apr Learn Probability
Sadika
In a standard deck of 52 playing cards, there are 2 black queens: the queen of spades and the queen of clubs.
Total number of possible outcomes (total number of cards): There are 52 cards in a standard deck.
Total number of favorable outcomes (black queens): There are 2 black queens in the deck.
Now, let's calculate the probability of drawing a black queen:
Probability=Number of favorable outcomesTotal number of possible outcomes
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Answered on 19 Apr Learn Probability
Sadika
To find the probability of getting a black ball, we need to consider the total number of balls in the bag and the number of black balls.
read lessAnswered on 19 Apr Learn Probability
Sadika
To find the probability of getting a number less than 3 when a die is thrown once, we need to determine the total number of favorable outcomes (rolling a number less than 3) and divide it by the total number of possible outcomes (rolling any number on the die).
Given:
Total number of possible outcomes: There are 6 possible outcomes when rolling a die.
Number of favorable outcomes (rolling a number less than 3): There are 2 favorable outcomes: rolling a 1 or rolling a 2.
Now, let's calculate the probability of getting a number less than 3:
read lessAnswered on 19 Apr Learn Probability
Sadika
To find the probability of drawing a card with an even number, we need to determine the total number of even-numbered cards in the bag and divide it by the total number of cards in the bag.
Given:
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Answered on 03/01/2022 Learn Statistics
Swati R.
NET JRF qualified and preparing for PhD..
First 10 Natural numbers are:- 1,2,3,4,5,6,7,8,9,10
Mean = Sum of all numbers/ total number of observations
= 1+2+3+4+5+6+7+8+9+10 / 10
= 55/ 10
= 5.5
Therefore, 5.5 is the mean of first 10 natural numbers
read lessAnswered on 19 Apr Learn Statistics
Sadika
The mean of the first n natural numbers can be calculated using the formula for the arithmetic mean:
Answered on 19 Apr Learn Statistics
Sadika
To show that the mode of the combined series obtained by combining the two series S1 and S2 is different from that of S1 and S2 taken separately, we first need to find the mode of each series individually and then compare it with the mode of the combined series.
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Answered on 19 Apr Learn Statistics
Sadika
To find the median for a frequency distribution, we need to use the relationship between the mean, median, and mode in a symmetrical distribution.
In a symmetrical distribution:
Given that the mode is 7.88 and the mean is 8.32, we can see that they are not equal. This suggests that the distribution is not perfectly symmetrical.
However, we can still estimate the median based on the mode and mean using the following relationship:
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