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Ramkrishna M. Class 7 Tuition trainer in Mumbai

Ramkrishna M.

Improve analytical skills of students for mathematics

Kandivali East, Mumbai, India - 400101.

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Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I am a retired qualified banker with abot 40 years experience and passion for teaching subjects specially maths, science across boards ICSE,CBSE and state boards enabling students to solve mathematical problems with ease. I have taught from home and taught at college under skill development programmes.

Languages Spoken

Malayalam Mother Tongue (Native)

English Proficient

Hindi Proficient

Marathi Proficient

Telugu Basic

Tamil Basic

Gujarati Basic

Education

Mumbai University 1976

Bachelor of Science (B.Sc.)

Indian Institute of Bankers 1982

Certified Associate of the Indian Institute of Bankers

Address

Kandivali East, Mumbai, India - 400101

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Teaches

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

5

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science, EVS, English

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics, English

Taught in School or College

No

State Syllabus Subjects taught

EVS, Mathematics, English, Science

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 8 do you teach for?

CBSE, ICSE and State

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 7 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Answers by Ramkrishna M. (5)

Answered on 22/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.6

Volume = circumference*height =132*25=3300cc Therefore, the capacity would be 3300/1000=3.3litres
Answers 5 Comments
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Answered on 22/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.6

The volume of cylindrical bowl with radius r and height l would be 2πrl=diameter*π*l=7*22/7*4=88cc. So for 250 patients it would be 22000cc. Since 1000cc =1litre, the hospital will require 22litres of soup.
Answers 4 Comments
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Answered on 20/08/2019 Learn CBSE +2 Tuition CBSE/Class 10/Mathematics

The easy method is square of last digit i.e 5*5 and n(n+1) of remaining digits to the left so even square of 125 is 15625 i.e 12*13 on the left and 5*5 on the right i.e 15625.
Answers 73 Comments
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Answered on 20/08/2019 Learn Tuition/Class VI-VIII Tuition +1 Tuition/Class VI-VIII Tuition/Mathematics

7/5+4/15 = 25/15=5/3 = 1 2/3
Answers 38 Comments
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Answered on 20/08/2019 Learn Tuition/Class VI-VIII Tuition/Mathematics

Since Ram has 4/5 Ankush would have 1/5 of stamps i.e = 900 stamps.
Answers 35 Comments
Dislike Bookmark

Teaches

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

5

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science, EVS, English

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics, English

Taught in School or College

No

State Syllabus Subjects taught

EVS, Mathematics, English, Science

No Reviews yet!

Answers by Ramkrishna M. (5)

Answered on 22/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.6

Volume = circumference*height =132*25=3300cc Therefore, the capacity would be 3300/1000=3.3litres
Answers 5 Comments
Dislike Bookmark

Answered on 22/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.6

The volume of cylindrical bowl with radius r and height l would be 2πrl=diameter*π*l=7*22/7*4=88cc. So for 250 patients it would be 22000cc. Since 1000cc =1litre, the hospital will require 22litres of soup.
Answers 4 Comments
Dislike Bookmark

Answered on 20/08/2019 Learn CBSE +2 Tuition CBSE/Class 10/Mathematics

The easy method is square of last digit i.e 5*5 and n(n+1) of remaining digits to the left so even square of 125 is 15625 i.e 12*13 on the left and 5*5 on the right i.e 15625.
Answers 73 Comments
Dislike Bookmark

Answered on 20/08/2019 Learn Tuition/Class VI-VIII Tuition +1 Tuition/Class VI-VIII Tuition/Mathematics

7/5+4/15 = 25/15=5/3 = 1 2/3
Answers 38 Comments
Dislike Bookmark

Answered on 20/08/2019 Learn Tuition/Class VI-VIII Tuition/Mathematics

Since Ram has 4/5 Ankush would have 1/5 of stamps i.e = 900 stamps.
Answers 35 Comments
Dislike Bookmark

Ramkrishna M. describes himself as Improve analytical skills of students for mathematics. He conducts classes in Class 7 Tuition. Ramkrishna is located in Kandivali East, Mumbai. Ramkrishna takes at students Home and Regular Classes- at his Home. He has 5 years of teaching experience . Ramkrishna has completed Bachelor of Science (B.Sc.) from Mumbai University in 1976. HeĀ is well versed in Malayalam, English, Hindi, Telugu, Tamil, Marathi and Gujarati.

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