Bibvewadi, Pune, India - 411037.
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Hindi Mother Tongue (Native)
English Proficient
German Basic
Vishwakarma institute of technology 2014
Bachelor of Technology (B.Tech.)
Bibvewadi, Pune, India - 411037
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1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
ICSE, IGCSE, CBSE
CBSE Subjects taught
German, Mathematics, Science, Computer Practices
ICSE Subjects taught
Mathematics, Physics, Biology, Chemistry
IGCSE Subjects taught
Chemistry, Physics, Biology, Mathematics, German
Taught in School or College
No
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in German Language Classes
1
Profession
Tutor
Type of student requirements I cater to
To learn it as a Hobby, Seeking admission in German university, For Employment reasons, For School Curriculum, Migrating to a German speaking Country
Awards and Recognition
No
Levels of German Language I teach
A1 (Beginner)
Teach at
Home
Teaching Experience in detail in German Language Classes
I can teach A1 level of german
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
ICSE, CBSE, IGCSE
CBSE Subjects taught
German, Science, Mathematics
IGCSE Subjects taught
Mathematics, Science
Taught in School or College
No
Teaching Experience in detail in Class 6 Tuition
I have Teaching experience for more than a year.
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
ICSE, CBSE, IGCSE
CBSE Subjects taught
Science, Mathematics
IGCSE Subjects taught
Mathematics, Science
Taught in School or College
No
Teaching Experience in detail in Class 8 Tuition
I have overall teaching experience of more than a year
1. Which school boards of Class 10 do you teach for?
ICSE, IGCSE and CBSE
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Class 6 Tuition, Class 8 Tuition, Class 9 Tuition and German Language Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 07/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4
It can be solved easily by using Uniform acceleration equation: V=u+at ( where V= final velocity of the object, u = initial velocity, a = acceleration, t = time at which the velocity to be calculated)
Simply Putting the given value in equations: As initial velocity " u " is not given in the problem , assuming the trolley starts from rest, Therefore u=0, a= 2 cm /s^2 , t (given) = 3s ( given), V= final velocity after 3 sec to be calculated?
V= 0+(2x3) = 6cm/s or 0.06 m/s
Therefore Velocity after 3 sec will be 0.06 m/s
Answered on 02/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.1
First of all, One needs to understand the fundamental difference between Displacement and Distance; Displacement is vector Qty which has Magnitude as well as direction (For ex: I travelled 100m in north direction ) whereas distance has the only Magnitude ( For ex: I went 50 km ). Therefore Displacement could be zero if the Initial point and endpoint are the same but covered a certain distance. Ex: If a man starts running in a stadium having a circular track and reach back to its Initial point after 1 round, Then the Total distance covered here is Circumference of circular path whereas the Displacement is Zero as the initial point and endpoint are same.
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
ICSE, IGCSE, CBSE
CBSE Subjects taught
German, Mathematics, Science, Computer Practices
ICSE Subjects taught
Mathematics, Physics, Biology, Chemistry
IGCSE Subjects taught
Chemistry, Physics, Biology, Mathematics, German
Taught in School or College
No
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in German Language Classes
1
Profession
Tutor
Type of student requirements I cater to
To learn it as a Hobby, Seeking admission in German university, For Employment reasons, For School Curriculum, Migrating to a German speaking Country
Awards and Recognition
No
Levels of German Language I teach
A1 (Beginner)
Teach at
Home
Teaching Experience in detail in German Language Classes
I can teach A1 level of german
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
ICSE, CBSE, IGCSE
CBSE Subjects taught
German, Science, Mathematics
IGCSE Subjects taught
Mathematics, Science
Taught in School or College
No
Teaching Experience in detail in Class 6 Tuition
I have Teaching experience for more than a year.
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
ICSE, CBSE, IGCSE
CBSE Subjects taught
Science, Mathematics
IGCSE Subjects taught
Mathematics, Science
Taught in School or College
No
Teaching Experience in detail in Class 8 Tuition
I have overall teaching experience of more than a year
Answered on 07/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4
It can be solved easily by using Uniform acceleration equation: V=u+at ( where V= final velocity of the object, u = initial velocity, a = acceleration, t = time at which the velocity to be calculated)
Simply Putting the given value in equations: As initial velocity " u " is not given in the problem , assuming the trolley starts from rest, Therefore u=0, a= 2 cm /s^2 , t (given) = 3s ( given), V= final velocity after 3 sec to be calculated?
V= 0+(2x3) = 6cm/s or 0.06 m/s
Therefore Velocity after 3 sec will be 0.06 m/s
Answered on 02/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.1
First of all, One needs to understand the fundamental difference between Displacement and Distance; Displacement is vector Qty which has Magnitude as well as direction (For ex: I travelled 100m in north direction ) whereas distance has the only Magnitude ( For ex: I went 50 km ). Therefore Displacement could be zero if the Initial point and endpoint are the same but covered a certain distance. Ex: If a man starts running in a stadium having a circular track and reach back to its Initial point after 1 round, Then the Total distance covered here is Circumference of circular path whereas the Displacement is Zero as the initial point and endpoint are same.
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Bibvewadi, Pune 
