Estimated Fees in India
₹ 300 to ₹ 500 per hour
Find Quantitative Aptitude Coaching Fees in your locality
Since childhood, I have been good with numbers and had a flair for mathematics. I carried this passion forward to pursue my Masters in Mathematics & Computing from IIT Kharagpur. I have been working as a Statistical Analyst in the industry now. However, I feel I can do a much better job at service the society by teaching what I am strongest at, Quantitative Aptitude. I have excellent quant skills, and would love to coach competitive exam aspirants into honing their skills too. I have recently started with my first student teaching her quant, and it's been such an amazing journey so far. If you are interested, kindly get in touch and I promise you it will be a wonderful experience for both of us.
I have 5 years of corporate work experience with firms like American Express, ZS Associates and Reliance Jio. Among the toppers during the academic career. Won many competitions, scholarships and awards. Also involved in social projects - part of 'Teach India.
I can teach each and every topics very easily and make it stronger for the students. I have an experience of more than 2 years in teaching Aptitude and reasoning for various students of banking, Ssc, rrb, and CRT. So far worked in software institution and CRT classes in jntu manthini and jntu sultanpur.
i have cleared SSC CGL EXAmination, i have cleared IBPS PO EXAm. i am preparing for civil services.
I have scored 96.93 in CAT 2016 and can give coaching in Quantitative Aptitude for CAT, SSC, BANK PO etc.
I am 25 years of age and teaching on a part-time basis at the moment. I have a large range of teaching experience from very young to adult. I enjoy teaching and am considered to have a caring approach and I try to make sure that learning takes place in a relaxed but studious situation.
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₹ 300 to ₹ 500
₹ 300 to ₹ 700
₹ 300 to ₹ 600
₹ 300 to ₹ 500
₹ 300 to ₹ 500
₹ 300 to ₹ 500
Answered on 15/11/2019 Learn Exam Coaching/Quantitative Aptitude
Varnika Gautam
Btech grad with 7 yrs of C++ coding experience and multiple websites running on 1st page of google
Let's say the no is X
X÷15= Y+14
X÷16= Z+15
If Y=X+1
And Z= X+1
We will get the no which is directly divisible by 15 and 16.
So we calculate the Lowest common multiple of 15 and 16. We get 240.
Now we need to subtract 1 from it to get the exact no.
Therefore the answer is 239
read lessAnswered on 09/10/2018 Learn Exam Coaching/Quantitative Aptitude
Balaji Mahesh Krishnan
23 years corporate trainer with 23 years experienced in sales and corporate training:
Answered on 19/09/2018 Learn Exam Coaching/Quantitative Aptitude
Selvi M.
Trainer
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