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Class 10 > Learn Mathematics > Is coaching required for class 10 cbse?
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Is coaching required for class 10 cbse?

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Learn Mathematics +2 BTech Tuition Class 9

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Professional trainer with 6+ years of teaching experience

Its fully your choice If you are able to study by your own then no need for coaching Only proper management is required
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SME, Tutor and Trainer for School Level, University level and Corporates

Yes must required.
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Tutor

For Class X coaching is not necessary.However tuition may be helpful if the student is not confident in the subjects he is studying because nowadays with increased syllabus and less time given teachers of schools are not able to help and guide the students ad per requirement.
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Chemistry Tutor

yes, coaching or Groups classes build up your coffidence level.
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Chemistry Tutor

In depth study of concepts will not require any coaching. Just practice and practice. If u need guidance for that you will require coaching.
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Tutor

No there is no need of coaching. Tution is sufficient
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Tutor

Coaching in term of mentoring and motivation is a great mantra for success while Coaching in terms of only subject may help you in scoring well but will not help you to grasp knowledge
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Computer Teacher

Optional, depends on your personal requirements, and what specific help you require
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Mathematics and engineering

It depends on students.
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Yes ofcourse, tuition gives regular practice and can help in increasing potentials
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Tuitions are absolutely not required for CBSE class 1o science as the contents in NCERT are absolutely self explanatory.
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If x, y are two no then AM=(x+y)/2 and GM = (xy)^(1/2).
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If HCF (6, a) = 2 and LCM (6, a) = 60, then find a.
60 * 2 = 6 * a a= 10
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In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately.
Let the marks of mathematics be x Than marks of science be 28-x now according to question (x+3), (28-x-4) The product of new marks will be 180 So, (x+3) (28-x-4)=180 24x-x^2+72-3x=180 x^2-21x+108=0 x^2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 (x-9)=0...
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Is polynomial y4 + 4y2 + 5 have zeroes or not?
The polynomial y4 + 4y2 + 5 has no zero(s) because the roots are not real.
Veerendra

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