Taloja Phase 1, Mumbai, India - 410208.
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Marathi
Hindi
Sydenham college of commerce and economics Pursuing
Bachelor of Banking and Insurance
Taloja Phase 1, Mumbai, India - 410208
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS
ICSE Subjects taught
English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS
ICSE Subjects taught
English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS
ICSE Subjects taught
English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business
ICSE Subjects taught
English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business
ICSE Subjects taught
English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
2
Board
CBSE, State, ICSE
CBSE Subjects taught
Science, Hindi, English, EVS, Mathematics, Computers, Marathi, Sanskrit
ICSE Subjects taught
EVS, Hindi, Mathematics, Sanskrit, Marathi, English, Science, Social Studies
Taught in School or College
No
State Syllabus Subjects taught
EVS, English, Social Science, Hindi, Science, Sanskrit, Mathematics, Marathi
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Nursery-KG Tuition
2
Subject
EVS, Drawing, Mathematics, English
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
2
BCom Subject
Human Resource Management, International Business, Business Communication, Business Taxation, Personal Selling and Salesmanship, Business Organisation and Management, Office Management and Secretarial Practice, Banking Technology and Management, Investment Analysis, Portfolio Management & Wealth Management, Banking and Insurance, Auditing and Corporate Governance, E-Commerce, Retail Management, Stock and Commodity Markets, Banking Law and Operation, Event Management, Accounting Information Systems, Management Accounting, Company Law, Organisational Behaviour, International Finance, Financial Accounting, International Banking & Forex Management, Financial Management, Financial Markets and Institutions, Business Laws, Business Mathematics and Statistics, Advertising, Micro & Macro Economics, Public relations and Corporate Communication, Financial Analysis and Reporting, Business Ethics, Corporate Accounting, Risk Management, Cost Accounting, Marketing, Information Technology and Audit
Type of class
Regular Classes, Crash Course
Business Communication Language
English, Hindi
Class strength catered to
Group Classes
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Mathematics, Hindi, Accountancy, Economics, English
Taught in School or College
No
State Syllabus Subjects taught
Hindi, English, Mathematics, Economics, Business Studies, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Mathematics, Hindi, Accountancy, Economics, English
Taught in School or College
No
State Syllabus Subjects taught
Hindi, English, Mathematics, Business Studies, Education, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi
1. Which school boards of Class 8 do you teach for?
State, CBSE, ICSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BCom Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Class I-V Tuition and Nursery-KG Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a paid demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
Is this what you are looking for?
i <3 u
<3 means heart. So it is read as I love you.
This relation can be brought down by simple algebra like,
say, i+5 < 3u+5 => i<3u
The famous style is this,
Solve for i,
9x- 7i < 3 (3x -7u)
= 9x - 7i < 9x - 21u
= -7i < -21u (cancel out the 9x)
simplified: i <3 u !
therefore: I love you
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
elekinetically. Jokes aside, I know a people who are excellent at Math and some can definitely be classified as genius. What they do is understand the concept rather than learn how to simply answer the question.
This way you’d be surprised that they will figure out extensions of that math question without even properly studying it. The reason is that their concept is so strong and when they link that with their already capable logic the result is a quick and thorough understanding of the topic.
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
The function f(x)=x3+ln(x+1) is defined over (−1,∞) . The limit at −1 is −∞ , the limit at ∞ is ∞ . The derivative is
f′(x)=3x2+1x+1>0
so you know that the function is strictly increasing. Therefore the given equation has a single solution. Since f(2)>8 and f(1)<8 , the solution is inside the interval (1,2) .
You can determine an approximation with the desired accuracy with numerical methods.
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
I assume that, by ‘yn+1’, you mean the (n+1)th derivative of y with respect to x - this is often written (with the parentheses) as a superscript, e.g.
y(n+1)
In other words, you want to prove that:
ddxn+1(xnln(x))=n!x
I suggest that you edit the question to make your meaning clearer as, from the two answers submitted before mine, they didn’t understand you.
This doesn’t really count as a proof, but I think its a way to demonstrate why this is true.
From the product rule for differentiation,
dydx=xnddxln(x)+ln(x)ddxxn
=xnx+nxn−1ln(x)=xn−1+nxn−1ln(x)
Having differentiated once, we still have to differentiate a further n times.
dn+1ydxn+1=dndxn(xn−1+nxn−1ln(x))
From the sum rule for differentiation, we can split this into two parts:
dndxnxn−1+ndndxnxn−1ln(x)
Let’s look at the first part. When we differentiate an expression than contains a term that is a power of x, we reduce the power by 1. So, if we differentiate xb b times, we end up with a constant [ xb−b=x0 ], and if we differentiate again, we get a zero. In this case, we’re wanting to differentiate xn−1 n times, this means that the term eventually becomes zero. So, our problem simplifies to:
ndndxnxn−1ln(x)=ndn−1dxn−1(ddxxn−1ln(x))
Applying the product rule again:
=ndn−1dxn−1(xn−2+(n−1)xn−2ln(x))
Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:
ndn−1dxn−1(n−1)xn−2ln(x)
As (n−1) is a constant, we can move it outside the differentiation; I’ll also introduce the notation n[2]=n!(n−2)!
So, we have:
n[2]dn−1dxn−1xn−2ln(x)
Applying the product rule again:
n[2]dn−2dxn−2(xn−3+(n−2)xn−3ln(x))
Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:
n[3]dn−2dxn−2xn−3ln(x)
Continuing the pattern we get:
n[4]dn−3dxn−3xn−4ln(x)
n[5]dn−4dxn−4xn−5ln(x)
…
n[n−1]d2dx2x1ln(x)
n[n]ddxln(x)=n[n]x
As the coefficient is just n! , our answer is:
n!x
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS
ICSE Subjects taught
English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS
ICSE Subjects taught
English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS
ICSE Subjects taught
English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business
ICSE Subjects taught
English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
State, CBSE, ICSE
CBSE Subjects taught
English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business
ICSE Subjects taught
English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
2
Board
CBSE, State, ICSE
CBSE Subjects taught
Science, Hindi, English, EVS, Mathematics, Computers, Marathi, Sanskrit
ICSE Subjects taught
EVS, Hindi, Mathematics, Sanskrit, Marathi, English, Science, Social Studies
Taught in School or College
No
State Syllabus Subjects taught
EVS, English, Social Science, Hindi, Science, Sanskrit, Mathematics, Marathi
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Nursery-KG Tuition
2
Subject
EVS, Drawing, Mathematics, English
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
2
BCom Subject
Human Resource Management, International Business, Business Communication, Business Taxation, Personal Selling and Salesmanship, Business Organisation and Management, Office Management and Secretarial Practice, Banking Technology and Management, Investment Analysis, Portfolio Management & Wealth Management, Banking and Insurance, Auditing and Corporate Governance, E-Commerce, Retail Management, Stock and Commodity Markets, Banking Law and Operation, Event Management, Accounting Information Systems, Management Accounting, Company Law, Organisational Behaviour, International Finance, Financial Accounting, International Banking & Forex Management, Financial Management, Financial Markets and Institutions, Business Laws, Business Mathematics and Statistics, Advertising, Micro & Macro Economics, Public relations and Corporate Communication, Financial Analysis and Reporting, Business Ethics, Corporate Accounting, Risk Management, Cost Accounting, Marketing, Information Technology and Audit
Type of class
Regular Classes, Crash Course
Business Communication Language
English, Hindi
Class strength catered to
Group Classes
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Mathematics, Hindi, Accountancy, Economics, English
Taught in School or College
No
State Syllabus Subjects taught
Hindi, English, Mathematics, Economics, Business Studies, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Mathematics, Hindi, Accountancy, Economics, English
Taught in School or College
No
State Syllabus Subjects taught
Hindi, English, Mathematics, Business Studies, Education, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
Is this what you are looking for?
i <3 u
<3 means heart. So it is read as I love you.
This relation can be brought down by simple algebra like,
say, i+5 < 3u+5 => i<3u
The famous style is this,
Solve for i,
9x- 7i < 3 (3x -7u)
= 9x - 7i < 9x - 21u
= -7i < -21u (cancel out the 9x)
simplified: i <3 u !
therefore: I love you
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
elekinetically. Jokes aside, I know a people who are excellent at Math and some can definitely be classified as genius. What they do is understand the concept rather than learn how to simply answer the question.
This way you’d be surprised that they will figure out extensions of that math question without even properly studying it. The reason is that their concept is so strong and when they link that with their already capable logic the result is a quick and thorough understanding of the topic.
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
The function f(x)=x3+ln(x+1) is defined over (−1,∞) . The limit at −1 is −∞ , the limit at ∞ is ∞ . The derivative is
f′(x)=3x2+1x+1>0
so you know that the function is strictly increasing. Therefore the given equation has a single solution. Since f(2)>8 and f(1)<8 , the solution is inside the interval (1,2) .
You can determine an approximation with the desired accuracy with numerical methods.
Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics
I assume that, by ‘yn+1’, you mean the (n+1)th derivative of y with respect to x - this is often written (with the parentheses) as a superscript, e.g.
y(n+1)
In other words, you want to prove that:
ddxn+1(xnln(x))=n!x
I suggest that you edit the question to make your meaning clearer as, from the two answers submitted before mine, they didn’t understand you.
This doesn’t really count as a proof, but I think its a way to demonstrate why this is true.
From the product rule for differentiation,
dydx=xnddxln(x)+ln(x)ddxxn
=xnx+nxn−1ln(x)=xn−1+nxn−1ln(x)
Having differentiated once, we still have to differentiate a further n times.
dn+1ydxn+1=dndxn(xn−1+nxn−1ln(x))
From the sum rule for differentiation, we can split this into two parts:
dndxnxn−1+ndndxnxn−1ln(x)
Let’s look at the first part. When we differentiate an expression than contains a term that is a power of x, we reduce the power by 1. So, if we differentiate xb b times, we end up with a constant [ xb−b=x0 ], and if we differentiate again, we get a zero. In this case, we’re wanting to differentiate xn−1 n times, this means that the term eventually becomes zero. So, our problem simplifies to:
ndndxnxn−1ln(x)=ndn−1dxn−1(ddxxn−1ln(x))
Applying the product rule again:
=ndn−1dxn−1(xn−2+(n−1)xn−2ln(x))
Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:
ndn−1dxn−1(n−1)xn−2ln(x)
As (n−1) is a constant, we can move it outside the differentiation; I’ll also introduce the notation n[2]=n!(n−2)!
So, we have:
n[2]dn−1dxn−1xn−2ln(x)
Applying the product rule again:
n[2]dn−2dxn−2(xn−3+(n−2)xn−3ln(x))
Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:
n[3]dn−2dxn−2xn−3ln(x)
Continuing the pattern we get:
n[4]dn−3dxn−3xn−4ln(x)
n[5]dn−4dxn−4xn−5ln(x)
…
n[n−1]d2dx2x1ln(x)
n[n]ddxln(x)=n[n]x
As the coefficient is just n! , our answer is:
n!x
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