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Ashwini R. Class 6 Tuition trainer in Mumbai/>

Ashwini R.

Ace Tutor

Taloja Phase 1, Mumbai, India - 410208.

1 Student

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Enthusiastic about applying a passion for working with children that includes solid knowledge acquired from relevant courses.
- Committed to helping children reach their full potential by fostering a supportive learning environment.
- passion about the teaching field with a great teaching aptitude
- Excellent ability to reach to the target students knowledge grasping level and implement.
- Appropriate teaching methods and techniques. Thorough knowledge of the subject to be taught and its background.
- Fluency in English, Marathi and Hindi.
- Knowledge of utilizing all the modern teaching aids appropriately and effectively.
- Uncommon ability to create quick interests among the students about the subject.
- Knowledge of common student's psychology and high concern regarding the problems they face in the learning process.
- Follows a high standard of personal and work ethics.
- A friendly, approachable and hardworking individual with exceptional interest in providing tutoring services to assist students in comprehending topic-related concepts.
- Patient and pleasant, with a demonstrated ability in communicating with people from different backgrounds.
Special talent for:
- Recognizing variations in student backgrounds, abilities and learning styles.
- Interacting with students in a friendly and respectful manner, aiming to comprehend their specific learning abilities and limitations.
- Explaining concepts in easy to understand ways without overwhelming students

Languages Spoken

English

Marathi

Hindi

Education

Sydenham college of commerce and economics Pursuing

Bachelor of Banking and Insurance

Address

Taloja Phase 1, Mumbai, India - 410208

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Teaches

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS

ICSE Subjects taught

English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS

ICSE Subjects taught

English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS

ICSE Subjects taught

English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business

ICSE Subjects taught

English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business

ICSE Subjects taught

English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English

Class I-V Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

CBSE, State, ICSE

CBSE Subjects taught

Science, Hindi, English, EVS, Mathematics, Computers, Marathi, Sanskrit

ICSE Subjects taught

EVS, Hindi, Mathematics, Sanskrit, Marathi, English, Science, Social Studies

Taught in School or College

No

State Syllabus Subjects taught

EVS, English, Social Science, Hindi, Science, Sanskrit, Mathematics, Marathi

Nursery-KG Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Nursery-KG Tuition

2

Subject

EVS, Drawing, Mathematics, English

Taught in School or College

No

BCom Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BCom Tuition

2

BCom Subject

Human Resource Management, International Business, Business Communication, Business Taxation, Personal Selling and Salesmanship, Business Organisation and Management, Office Management and Secretarial Practice, Banking Technology and Management, Investment Analysis, Portfolio Management & Wealth Management, Banking and Insurance, Auditing and Corporate Governance, E-Commerce, Retail Management, Stock and Commodity Markets, Banking Law and Operation, Event Management, Accounting Information Systems, Management Accounting, Company Law, Organisational Behaviour, International Finance, Financial Accounting, International Banking & Forex Management, Financial Management, Financial Markets and Institutions, Business Laws, Business Mathematics and Statistics, Advertising, Micro & Macro Economics, Public relations and Corporate Communication, Financial Analysis and Reporting, Business Ethics, Corporate Accounting, Risk Management, Cost Accounting, Marketing, Information Technology and Audit

Type of class

Regular Classes, Crash Course

Business Communication Language

English, Hindi

Class strength catered to

Group Classes

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Mathematics, Hindi, Accountancy, Economics, English

Taught in School or College

No

State Syllabus Subjects taught

Hindi, English, Mathematics, Economics, Business Studies, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Mathematics, Hindi, Accountancy, Economics, English

Taught in School or College

No

State Syllabus Subjects taught

Hindi, English, Mathematics, Business Studies, Education, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 8 do you teach for?

State, CBSE, ICSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach BCom Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Class I-V Tuition and Nursery-KG Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a paid demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Ashwini R. (8)

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

Is this what you are looking for? i <3 u <3 means heart. So it is read as I love you. This relation can be brought down by simple algebra like, say, i+5 < 3u+5 => i<3u The famous style is this, Solve for i, 9x- 7i < 3 (3x -7u) = 9x - 7i < 9x - 21u = -7i < -21u... ...more

Is this what you are looking for?

i <3 u

 

<3 means heart. So it is read as I love you.

 

This relation can be brought down by simple algebra like,

say, i+5 < 3u+5 => i<3u

The famous style is this,

 

Solve for i,

9x- 7i < 3 (3x -7u)

= 9x - 7i < 9x - 21u

= -7i < -21u (cancel out the 9x)

simplified: i <3 u !

therefore: I love you

Answers 2 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

elekinetically. Jokes aside, I know a people who are excellent at Math and some can definitely be classified as genius. What they do is understand the concept rather than learn how to simply answer the question. This way you’d be surprised that they will figure out extensions of that math question... ...more

elekinetically. Jokes aside, I know a people who are excellent at Math and some can definitely be classified as genius. What they do is understand the concept rather than learn how to simply answer the question.

 

This way you’d be surprised that they will figure out extensions of that math question without even properly studying it. The reason is that their concept is so strong and when they link that with their already capable logic the result is a quick and thorough understanding of the topic.

Answers 5 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

When we estimate, we find an answer that is close to, but not exactly, the accurate answer for a problem.
Answers 5 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

The function f(x)=x3+ln(x+1) is defined over (−1,∞) . The limit at −1 is −∞ , the limit at ∞ is ∞ . The derivative is f′(x)=3x2+1x+1>0 so you know that the function is strictly increasing. Therefore the given equation has a single solution.... ...more

The function f(x)=x3+ln(x+1) is defined over (−1,∞) . The limit at −1 is −∞ , the limit at ∞ is ∞ . The derivative is

 

f′(x)=3x2+1x+1>0 

 

so you know that the function is strictly increasing. Therefore the given equation has a single solution. Since f(2)>8 and f(1)<8 , the solution is inside the interval (1,2) .

 

You can determine an approximation with the desired accuracy with numerical methods.

Answers 1 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +1 CBSE/Class 9/Mathematics

I assume that, by ‘yn+1’, you mean the (n+1)th derivative of y with respect to x - this is often written (with the parentheses) as a superscript, e.g. y(n+1) In other words, you want to prove that: ddxn+1(xnln(x))=n!x I suggest that you edit the question to make your meaning... ...more

I assume that, by ‘yn+1’, you mean the (n+1)th derivative of y with respect to x - this is often written (with the parentheses) as a superscript, e.g.

 

y(n+1) 

 

In other words, you want to prove that:

 

ddxn+1(xnln(x))=n!x 

 

I suggest that you edit the question to make your meaning clearer as, from the two answers submitted before mine, they didn’t understand you.

 

 

 

This doesn’t really count as a proof, but I think its a way to demonstrate why this is true.

 

From the product rule for differentiation,

 

dydx=xnddxln(x)+ln(x)ddxxn 

 

=xnx+nxn−1ln(x)=xn−1+nxn−1ln(x) 

 

Having differentiated once, we still have to differentiate a further n times.

 

dn+1ydxn+1=dndxn(xn−1+nxn−1ln(x)) 

 

From the sum rule for differentiation, we can split this into two parts:

 

dndxnxn−1+ndndxnxn−1ln(x) 

 

Let’s look at the first part. When we differentiate an expression than contains a term that is a power of x, we reduce the power by 1. So, if we differentiate xb b times, we end up with a constant [ xb−b=x0 ], and if we differentiate again, we get a zero. In this case, we’re wanting to differentiate xn−1 n times, this means that the term eventually becomes zero. So, our problem simplifies to:

 

ndndxnxn−1ln(x)=ndn−1dxn−1(ddxxn−1ln(x)) 

 

Applying the product rule again:

 

=ndn−1dxn−1(xn−2+(n−1)xn−2ln(x)) 

 

Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:

 

ndn−1dxn−1(n−1)xn−2ln(x) 

 

As (n−1) is a constant, we can move it outside the differentiation; I’ll also introduce the notation n[2]=n!(n−2)! 

 

So, we have:

 

n[2]dn−1dxn−1xn−2ln(x) 

 

Applying the product rule again:

 

n[2]dn−2dxn−2(xn−3+(n−2)xn−3ln(x)) 

 

Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:

 

n[3]dn−2dxn−2xn−3ln(x) 

 

Continuing the pattern we get:

 

n[4]dn−3dxn−3xn−4ln(x) 

 

n[5]dn−4dxn−4xn−5ln(x) 

 

 

n[n−1]d2dx2x1ln(x) 

 

n[n]ddxln(x)=n[n]x 

 

As the coefficient is just n! , our answer is:

 

n!x 

 

 

Answers 2 Comments
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Teaches

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS

ICSE Subjects taught

English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS

ICSE Subjects taught

English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, English, Social Science, Marathi, Hindi, Sanskrit, Mathematics, EVS

ICSE Subjects taught

English, Biology, Geography, Marathi, Chemistry, EVS, History, Physics, Hindi, Sanskrit, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Marathi, Sanskrit, EVS, Science, Hindi, Social science

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business

ICSE Subjects taught

English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

English, Sanskrit, Mathematics, Science, Marathi, Accountancy, Information and Comunication Technology, Hindi, Social science, Elements of business

ICSE Subjects taught

English, Physics, Economic Application, Chemistry, EVS, Geography, Biology, Hindi, History and Civics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Social Science, Mathematics, EVS, Sanskrit, Marathi, English

Class I-V Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

CBSE, State, ICSE

CBSE Subjects taught

Science, Hindi, English, EVS, Mathematics, Computers, Marathi, Sanskrit

ICSE Subjects taught

EVS, Hindi, Mathematics, Sanskrit, Marathi, English, Science, Social Studies

Taught in School or College

No

State Syllabus Subjects taught

EVS, English, Social Science, Hindi, Science, Sanskrit, Mathematics, Marathi

Nursery-KG Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Nursery-KG Tuition

2

Subject

EVS, Drawing, Mathematics, English

Taught in School or College

No

BCom Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BCom Tuition

2

BCom Subject

Human Resource Management, International Business, Business Communication, Business Taxation, Personal Selling and Salesmanship, Business Organisation and Management, Office Management and Secretarial Practice, Banking Technology and Management, Investment Analysis, Portfolio Management & Wealth Management, Banking and Insurance, Auditing and Corporate Governance, E-Commerce, Retail Management, Stock and Commodity Markets, Banking Law and Operation, Event Management, Accounting Information Systems, Management Accounting, Company Law, Organisational Behaviour, International Finance, Financial Accounting, International Banking & Forex Management, Financial Management, Financial Markets and Institutions, Business Laws, Business Mathematics and Statistics, Advertising, Micro & Macro Economics, Public relations and Corporate Communication, Financial Analysis and Reporting, Business Ethics, Corporate Accounting, Risk Management, Cost Accounting, Marketing, Information Technology and Audit

Type of class

Regular Classes, Crash Course

Business Communication Language

English, Hindi

Class strength catered to

Group Classes

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Mathematics, Hindi, Accountancy, Economics, English

Taught in School or College

No

State Syllabus Subjects taught

Hindi, English, Mathematics, Economics, Business Studies, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Mathematics, Hindi, Accountancy, Economics, English

Taught in School or College

No

State Syllabus Subjects taught

Hindi, English, Mathematics, Business Studies, Education, Organisation of Commerce, Accountancy, Statistics, Secretarial Practices , Marathi

No Reviews yet!

Answers by Ashwini R. (8)

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

Is this what you are looking for? i <3 u <3 means heart. So it is read as I love you. This relation can be brought down by simple algebra like, say, i+5 < 3u+5 => i<3u The famous style is this, Solve for i, 9x- 7i < 3 (3x -7u) = 9x - 7i < 9x - 21u = -7i < -21u... ...more

Is this what you are looking for?

i <3 u

 

<3 means heart. So it is read as I love you.

 

This relation can be brought down by simple algebra like,

say, i+5 < 3u+5 => i<3u

The famous style is this,

 

Solve for i,

9x- 7i < 3 (3x -7u)

= 9x - 7i < 9x - 21u

= -7i < -21u (cancel out the 9x)

simplified: i <3 u !

therefore: I love you

Answers 2 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

elekinetically. Jokes aside, I know a people who are excellent at Math and some can definitely be classified as genius. What they do is understand the concept rather than learn how to simply answer the question. This way you’d be surprised that they will figure out extensions of that math question... ...more

elekinetically. Jokes aside, I know a people who are excellent at Math and some can definitely be classified as genius. What they do is understand the concept rather than learn how to simply answer the question.

 

This way you’d be surprised that they will figure out extensions of that math question without even properly studying it. The reason is that their concept is so strong and when they link that with their already capable logic the result is a quick and thorough understanding of the topic.

Answers 5 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

When we estimate, we find an answer that is close to, but not exactly, the accurate answer for a problem.
Answers 5 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +2 CBSE/Class 1/Maths CBSE/Class 9/Mathematics

The function f(x)=x3+ln(x+1) is defined over (−1,∞) . The limit at −1 is −∞ , the limit at ∞ is ∞ . The derivative is f′(x)=3x2+1x+1>0 so you know that the function is strictly increasing. Therefore the given equation has a single solution.... ...more

The function f(x)=x3+ln(x+1) is defined over (−1,∞) . The limit at −1 is −∞ , the limit at ∞ is ∞ . The derivative is

 

f′(x)=3x2+1x+1>0 

 

so you know that the function is strictly increasing. Therefore the given equation has a single solution. Since f(2)>8 and f(1)<8 , the solution is inside the interval (1,2) .

 

You can determine an approximation with the desired accuracy with numerical methods.

Answers 1 Comments
Dislike Bookmark

Answered on 11/12/2021 Learn CBSE/Class 10/Mathematics +1 CBSE/Class 9/Mathematics

I assume that, by ‘yn+1’, you mean the (n+1)th derivative of y with respect to x - this is often written (with the parentheses) as a superscript, e.g. y(n+1) In other words, you want to prove that: ddxn+1(xnln(x))=n!x I suggest that you edit the question to make your meaning... ...more

I assume that, by ‘yn+1’, you mean the (n+1)th derivative of y with respect to x - this is often written (with the parentheses) as a superscript, e.g.

 

y(n+1) 

 

In other words, you want to prove that:

 

ddxn+1(xnln(x))=n!x 

 

I suggest that you edit the question to make your meaning clearer as, from the two answers submitted before mine, they didn’t understand you.

 

 

 

This doesn’t really count as a proof, but I think its a way to demonstrate why this is true.

 

From the product rule for differentiation,

 

dydx=xnddxln(x)+ln(x)ddxxn 

 

=xnx+nxn−1ln(x)=xn−1+nxn−1ln(x) 

 

Having differentiated once, we still have to differentiate a further n times.

 

dn+1ydxn+1=dndxn(xn−1+nxn−1ln(x)) 

 

From the sum rule for differentiation, we can split this into two parts:

 

dndxnxn−1+ndndxnxn−1ln(x) 

 

Let’s look at the first part. When we differentiate an expression than contains a term that is a power of x, we reduce the power by 1. So, if we differentiate xb b times, we end up with a constant [ xb−b=x0 ], and if we differentiate again, we get a zero. In this case, we’re wanting to differentiate xn−1 n times, this means that the term eventually becomes zero. So, our problem simplifies to:

 

ndndxnxn−1ln(x)=ndn−1dxn−1(ddxxn−1ln(x)) 

 

Applying the product rule again:

 

=ndn−1dxn−1(xn−2+(n−1)xn−2ln(x)) 

 

Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:

 

ndn−1dxn−1(n−1)xn−2ln(x) 

 

As (n−1) is a constant, we can move it outside the differentiation; I’ll also introduce the notation n[2]=n!(n−2)! 

 

So, we have:

 

n[2]dn−1dxn−1xn−2ln(x) 

 

Applying the product rule again:

 

n[2]dn−2dxn−2(xn−3+(n−2)xn−3ln(x)) 

 

Applying the sum rule again, the first term again reduces to zero with continued differentiation, so we are left with:

 

n[3]dn−2dxn−2xn−3ln(x) 

 

Continuing the pattern we get:

 

n[4]dn−3dxn−3xn−4ln(x) 

 

n[5]dn−4dxn−4xn−5ln(x) 

 

 

n[n−1]d2dx2x1ln(x) 

 

n[n]ddxln(x)=n[n]x 

 

As the coefficient is just n! , our answer is:

 

n!x 

 

 

Answers 2 Comments
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Ashwini R. describes herself as Ace Tutor. She conducts classes in BCom Tuition, Class 10 Tuition and Class 11 Tuition. Ashwini is located in Taloja Phase 1, Mumbai. Ashwini takes Regular Classes- at her Home. She has 2 years of teaching experience . Ashwini is pursuing Bachelor of Banking and Insurance from Sydenham college of commerce and economics. She is well versed in English, Marathi and Hindi.

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